在宿管系统中，引入排行榜功能可以有效激励学生遵守宿舍规定，提高生活质量。本文将介绍如何在宿管系统中实现排行榜功能，并通过具体的代码示例来展示实现过程。
首先，我们需要一个基础的数据表结构来存储每个宿舍的表现分数。我们可以使用MySQL数据库来创建这样的数据表：
CREATE TABLE DormitoryScores (
dormitory_id INT PRIMARY KEY,
score INT NOT NULL DEFAULT 0
);
这个表包含两个字段：`dormitory_id`用于唯一标识宿舍，`score`用于记录宿舍的得分。
接下来，我们将使用Python语言来实现排行榜功能。首先定义一个函数来更新宿舍的得分：
def update_score(dormitory_id, points):
import mysql.connector
from mysql.connector import Error
try:
connection = mysql.connector.connect(host='localhost',
database='dormitory_system',
user='root',
password='password')
cursor = connection.cursor()
query = "UPDATE DormitoryScores SET score = score + %s WHERE dormitory_id = %s"
cursor.execute(query, (points, dormitory_id))
connection.commit()
except Error as e:
print("Error while connecting to MySQL", e)
finally:
if connection.is_connected():
cursor.close()
connection.close()
此外，我们还需要一个函数来获取当前的排行榜：
def get_ranking():
import mysql.connector
from mysql.connector import Error
try:
connection = mysql.connector.connect(host='localhost',
database='dormitory_system',
user='root',
password='password')
cursor = connection.cursor()
query = "SELECT dormitory_id, score FROM DormitoryScores ORDER BY score DESC LIMIT 10"
cursor.execute(query)
ranking = cursor.fetchall()
return ranking
except Error as e:
print("Error while connecting to MySQL", e)
finally:
if connection.is_connected():
cursor.close()
connection.close()
通过这两个函数，我们可以轻松地更新宿舍得分并获取最新的排行榜。